how does RE# find the leftmost-longest match efficiently? remember the bidirectional scanning we mentioned earlier - run the DFA right to left to find all possible match starts, then run a reversed DFA left to right to find the ends. the leftmost start paired with the rightmost end gives you leftmost-longest. two linear DFA scans, no backtracking, no ambiguity.
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mdaiter/ane — Early reverse engineering with working Python and Objective-C samples, documenting the ANECompiler framework and IOKit dispatch.